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(P)=-14P^2+1540P-25.200
We move all terms to the left:
(P)-(-14P^2+1540P-25.200)=0
We get rid of parentheses
14P^2-1540P+P+25.200=0
We add all the numbers together, and all the variables
14P^2-1539P+25.2=0
a = 14; b = -1539; c = +25.2;
Δ = b2-4ac
Δ = -15392-4·14·25.2
Δ = 2367109.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1539)-\sqrt{2367109.8}}{2*14}=\frac{1539-\sqrt{2367109.8}}{28} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1539)+\sqrt{2367109.8}}{2*14}=\frac{1539+\sqrt{2367109.8}}{28} $
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